When a metal surface is illuminated by light of wavelength \(\lambda\), the stopping potential is \(9 V\). When the same surface is illuminated by light of wavelength \(2 \lambda\), stopping potential is \(3 V\). The threshold wavelength for this surface is:

[JEE Main 2024, 31 Jan (Shift 1)]

Question

When a metal surface is illuminated by light of wavelength \(\lambda\), the stopping potential is \(9 V\). When the same surface is illuminated by light of wavelength \(2 \lambda\), stopping potential is \(3 V\). The threshold wavelength for this surface is:

[JEE Main 2024, 31 Jan (Shift 1)]

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When a metal surface is illuminated by light of wavelength \(\lambda\), the stopping potential is \(9 V\). When the same…

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