A metal complex with a formula $\mathrm{MC}{l}_{4}\cdot 3{\mathrm{NH}}_{3}$ is involved in ${\mathrm{sp}}^{3}{\mathrm{d}}^{2}$ hybridisation. It upon reaction with excess of ${\mathrm{AgNO}}_{3}$ solution gives ' x' moles of $\mathrm{AgCl}$. Consider ' x ' is equal to the number of lone pairs of electron present in central atom of ${\mathrm{BrF}}_{5}$. Then the number of geometrical isomers exhibited by the complex is ________ [JEE Main 2025, 4 Apr (Shift 2)]

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Correct answer: b) 2. One lone pair in ${\mathrm{BrF}}_{5}$⇒ 1 mol AgCl formed. Complex formula: $[\mathrm{M}{({\mathrm{NH}}_{3})}_{3}{\mathrm{Cl}}_{3}]\mathrm{Cl}$ Type ${\mathrm{MA}}_{3}{\mathrm{B}}_{3}$ complex ⇒ shows 2 geometrical isomers: facial (fac) meridional (mer)

A metal complex with a formula \(\mathrm{MC}{l}_{4}\cdot 3{\mathrm{NH}}_{3}\) is involved in \({\mathrm{sp}}^{3}{\mathrm…

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