Let \(\alpha\) and \(\beta\) respectively be the maximum and the minimum values of the function \( f(\theta)=4\left(\sin…
Let \(\alpha\) and \(\beta\) respectively be the maximum and the minimum values of the function
\( f(\theta)=4\left(\sin ^4\left(\frac{7 \pi}{2}-\theta\right)+\sin ^4(11 \pi+\theta)\right) -2\left(\sin ^6\left(\frac{3 \pi}{2}-\theta\right)+\sin ^6(9 \pi-\theta)\right)\). Then \(\alpha +2\beta\) is equal to:
[JEE Main 2026, 23 Jan (Shift 2)]
\(5\)
Given:
\( f(\theta)=4\left(\sin ^4\left(\frac{7 \pi}{2}-\theta\right)+\sin ^4(11 \pi+\theta)\right) -2\left(\sin ^6\left(\frac{3 \pi}{2}-\theta\right)+\sin ^6(9 \pi-\theta)\right)\)
\(\Rightarrow f(\theta)=4\left(\cos ^4(\theta)+\sin ^4(\theta)\right)-2\left(\cos ^6 \theta+\sin ^6 \theta\right)\)
\(\Rightarrow f(\theta)=4\left(1-2 \sin ^2 \theta \cos ^2 \theta\right)-2\left(1-3 \sin ^2 \theta \cos ^2 \theta\right)\)
\(\Rightarrow f(\theta)=2-2 \sin ^2 \theta \cos ^2 \theta\)
\(\Rightarrow f(\theta)=2-\frac{\sin ^2(2 \theta)}{2}\)
So, \(\alpha=f(\theta)_{\max }=2\),
\(\beta=f(\theta)_{\min }=\frac{3}{2}\)
\(\Rightarrow \alpha+2 \beta=5\)
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