Consider the following low-spin complexes \({K}_{3}\left[Co{\left(N{O}_{2}\right)}_{6}\right],{K}_{4}\left[Fe(CN{)}_{6}\…
Consider the following low-spin complexes
\({K}_{3}\left[Co{\left(N{O}_{2}\right)}_{6}\right],{K}_{4}\left[Fe(CN{)}_{6}\right],\) \({K}_{3}\left[Fe(CN{)}_{6}\right],C{u}_{2}\left[Fe(CN{)}_{6}\right]\) and \(Z{n}_{2}\left[Fe(CN{)}_{6}\right].\)
The sum of the spin-only magnetic moment values of complexes having yellow colour is _________ B.M. (answer in nearest integer)
[JEE Main 2025, 29 Jan (Shift 2)]
0
The complexes having yellow colour are:
K₃[Co(NO₂)₆] and K₄[Fe(CN)₆]
Now, calculate spin-only magnetic moment using number of unpaired electrons (n):
[Co(NO₂)₆]³⁻ → Co³⁺ = d⁶, strong field ligand ⇒ low spin ⇒ n = 0 ⇒ μ = 0
[Fe(CN)₆]⁴⁻ → Fe²⁺ = d⁶, strong field ligand ⇒ low spin ⇒ n = 0 ⇒ μ = 0
Thus, total magnetic moment = 0 + 0 = 0 B.M.
Final Answer: 0
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