The correct option for the mass of $\mathrm{CO}_2$ produced by heating $20 \mathrm{~g}$ of $20 \%$ pure limestone is (Atomic mass of $\mathrm{Ca}=40$u) $\left[{\mathrm{CaCO}}_{3}\overset{1200\mathrm{K}}{\to }\mathrm{CaO}+{\mathrm{CO}}_{2}\right]$

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The correct option for the mass of \(\mathrm{CO}_2\) produced by heating \(20 \mathrm{~g}\) of \(20 \%\) pure limestone …

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