An organic compound has 42.1% carbon, 6.4% hydrogen and remainder is oxygen. If its molecular weight is 342, then its mo…

Given:

C = 42.1%, H = 6.4%, O = 100 − 48.5 = 51.5%

Divide by atomic masses:

C → 42.1 ÷ 12 = 3.508

H → 6.4 ÷ 1 = 6.4

O → 51.5 ÷ 16 = 3.219

Divide all by 3.219:

C ≈ 1.09, H ≈ 1.99, O ≈ 1

Empirical formula ≈ C₁H₂O₁

Empirical mass = 12 + 2 + 16 = 30

n = 342 ÷ 30 = 11.4 ≈ 11

Molecular formula = C₁₁H₂₂O₁₁

Answer: Option D