🏫 Board🧲 Physics

According to Gauss' law of electrostatics

\({ϕ}_{E}=\frac{{ϵ}_{0}}{2}\)

\({ϕ}_{E}=\frac{q}{{ϵ}_{0}}\)

\({ϕ}_{E}=q{ϵ}_{0}\)

\({ϕ}_{E}=\frac{1}{q{ϵ}_{0}}\)

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