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The acceptor level of a p-type semiconductor is \(6 eV\). The maximum wavelength of light which can create a hole would …

Q1

The acceptor level of a p-type semiconductor is \(6 eV\). The maximum wavelength of light which can create a hole would be : Given \(hc =1242 eV nm\).

[JEE Main 2024, 6 Apr (Shift 2)]

a

\(407 nm\)

b

\(207 nm\)

c

\(103.5 nm\)

d

\(414 nm\)

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