Semiconductor Electronics: Materials, Devices and Simple Circuits

barrier height and the depletion layer width both decrease. When p-n junction is forward biased: • The barrier potential decreases. • The depletion layer width decreases due to carrier injection.

Identify that Si doped with a pentavalent element introduces extra electrons, and the energy required to free these electrons is very low.

(B) 0.05 eV

When a p-n junction diode is reverse biased, a negative voltage is applied to the p-side and a positive voltage to the n-side, causing the depletion region to widen and the barrier potential to increase. This creates a high resistance that prevents the flow of majority carriers, so only a very small current (reverse saturation current) due to minority carriers flows, making the diode act as an open switch.

When germanium (Ge), a group-IV element, is doped with arsenic (As), a group-V element, it creates an n-type semiconductor. Arsenic contributes extra electrons (conduction electrons) to the material because it has five valence electrons compared to four in germanium. These extra electrons become free to conduct electricity, thus increasing the number of conduction electrons. Thus, the effect of doping Ge with As is :

the number of conduction electrons increases.

Due to doping, the number of conduction electrons increases.

When a p-n junction diode is reverse biased, a negative voltage is applied to the p-side and a positive voltage to the n-side, causing the depletion region to widen and the barrier potential to increase. This creates a high resistance that prevents the flow of majority carriers, so only a very small current (reverse saturation current) due to minority carriers flows, making the diode act as an open switch.

When a p-n junction diode is reverse biased, a negative voltage is applied to the p-side and a positive voltage to the n-side, causing the depletion region to widen and the barrier potential to increase. This creates a high resistance that prevents the flow of majority carriers, so only a very small current (reverse saturation current) due to minority carriers flows, making the diode act as an open switch.

Identify that Si doped with a pentavalent element introduces extra electrons, and the energy required to free these electrons is very low.

(B) 0.05 eV

When germanium (Ge), a group-IV element, is doped with arsenic (As), a group-V element, it creates an n-type semiconductor. Arsenic contributes extra electrons (conduction electrons) to the material because it has five valence electrons compared to four in germanium. These extra electrons become free to conduct electricity, thus increasing the number of conduction electrons. Thus, the effect of doping Ge with As is :

the number of conduction electrons increases.

Due to doping, the number of conduction electrons increases.

An n-type semiconductor is obtained by doping intrinsic silicon with a pentavalent element from Group 15, such as phosphorus (P), arsenic (As), or antimony (Sb). These impurities provide extra electrons, which become the majority charge carriers in the semiconductor.

An n-type semiconductor is obtained by doping intrinsic silicon with a pentavalent element from Group 15, such as phosphorus (P), arsenic (As), or antimony (Sb). These impurities provide extra electrons, which become the majority charge carriers in the semiconductor.

Correct option is : (C) The barrier height and the depletion layer width both decrease. When p-n junction is forward biased: • The barrier potential decreases. • The depletion layer width decreases due to carrier injection.

Under reverse bias, the electric field pulls majority carriers (holes on the p-side, electrons on the n-side) away from the junction, increasing the depletion region. The small reverse current is due to minority carriers moving across the junction (holes from n-side to p-side, and electrons from p-side to n-side). so, statement B is not true.

Due to doping, the number of conduction electrons increases.

barrier height and the depletion layer width both decrease. When p-n junction is forward biased: • The barrier potential decreases. • The depletion layer width decreases due to carrier injection.

Under reverse bias, the electric field pulls majority carriers (holes on the p-side, electrons on the n-side) away from the junction, increasing the depletion region. The small reverse current is due to minority carriers moving across the junction (holes from n-side to p-side, and electrons from p-side to n-side). so, statement B is not true.

Identify that Si doped with a pentavalent element introduces extra electrons, and the energy required to free these electrons is very low.

(B) 0.05 eV

Correct option is : (C) The barrier height and the depletion layer width both decrease. When p-n junction is forward biased: • The barrier potential decreases. • The depletion layer width decreases due to carrier injection.

When a p-n junction diode is reverse biased, a negative voltage is applied to the p-side and a positive voltage to the n-side, causing the depletion region to widen and the barrier potential to increase. This creates a high resistance that prevents the flow of majority carriers, so only a very small current (reverse saturation current) due to minority carriers flows, making the diode act as an open switch.

Due to doping, the number of conduction electrons increases.

Due to doping, the number of conduction electrons increases.

When a p-n junction diode is reverse biased, a negative voltage is applied to the p-side and a positive voltage to the n-side, causing the depletion region to widen and the barrier potential to increase. This creates a high resistance that prevents the flow of majority carriers, so only a very small current (reverse saturation current) due to minority carriers flows, making the diode act as an open switch.

barrier height and the depletion layer width both decrease. When p-n junction is forward biased: • The barrier potential decreases. • The depletion layer width decreases due to carrier injection.

For AND gate

$$\begin{gathered} \mathrm{y} = \mathrm{A} . \mathrm{B} \\ \mathrm{Then} \mathrm{NOT}\hspace{0.17em}\mathrm{gate} \mathrm{is} \mathrm{there} \mathrm{so} \\ \mathrm{y} = \overline{\mathrm{A} . \mathrm{B}} \end{gathered}$$

When germanium (Ge), a group-IV element, is doped with arsenic (As), a group-V element, it creates an n-type semiconductor. Arsenic contributes extra electrons (conduction electrons) to the material because it has five valence electrons compared to four in germanium. These extra electrons become free to conduct electricity, thus increasing the number of conduction electrons. Thus, the effect of doping Ge with As is :

the number of conduction electrons increases.

(c) Solar cells don't need an external bias, as they generate their own voltage when exposed to light.
E (Correct): LEDs must be forwardbiased to emit light.
Other statements are incorrect.
Thus, the correct choice is (c) B, E Only.
Work done

Correct option is : (C) The barrier height and the depletion layer width both decrease. When p-n junction is forward biased: • The barrier potential decreases. • The depletion layer width decreases due to carrier injection.

Correct option is : (C) The barrier height and the depletion layer width both decrease. When p-n junction is forward biased: • The barrier potential decreases. • The depletion layer width decreases due to carrier injection.

$$\begin{gathered} E=h\nu \\ E=\frac{hc}{\lambda } \end{gathered}$$

$\Rightarrow {\lambda }_{max}=\frac{hc}{E}$

$\frac{=1242}{6}=207nm$

Under reverse bias, the electric field pulls majority carriers (holes on the p-side, electrons on the n-side) away from the junction, increasing the depletion region. The small reverse current is due to minority carriers moving across the junction (holes from n-side to p-side, and electrons from p-side to n-side). so, statement B is not true.

Identify that Si doped with a pentavalent element introduces extra electrons, and the energy required to free these electrons is very low.

(B) 0.05 eV

Due to doping, the number of conduction electrons increases.

An n-type semiconductor is obtained by doping intrinsic silicon with a pentavalent element from Group 15, such as phosphorus (P), arsenic (As), or antimony (Sb). These impurities provide extra electrons, which become the majority charge carriers in the semiconductor.

When a p-n junction diode is reverse biased, a negative voltage is applied to the p-side and a positive voltage to the n-side, causing the depletion region to widen and the barrier potential to increase. This creates a high resistance that prevents the flow of majority carriers, so only a very small current (reverse saturation current) due to minority carriers flows, making the diode act as an open switch.