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An alternating voltage \(V(t)=220 \sin 100 \pi t\) volt is applied to a purely resistive load of \(50 \Omega\). The time…

Q1

An alternating voltage \(V(t)=220 \sin 100 \pi t\) volt is applied to a purely resistive load of \(50 \Omega\). The time taken for the current to rise from half of the peak value to the peak value is:

a

\(2.2 ms\)

b

\(7.2 ms\)

c

\(3.3 ms\)

d

\(5 ms\)

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