An alternating current is given by \(I={I}_{A}\sin \omega t+{I}_{B}\cos \omega t\). The r.m.s current will be [JEE Main …

\(\frac{\sqrt{{I}_{A}^{2}+{I}_{B}^{2}}}{2}\)

\(\frac{\left|{I}_{A}+{I}_{B}\right|}{\sqrt{2}}\)

\(\sqrt{{I}_{A}^{2}+{I}_{B}^{2}}\)

\(\sqrt{\frac{{I}_{A}^{2}+{I}_{B}^{2}}{2}}\)