The standard cell potential of the following cell

\(Zn|Z{n}^{{2}^{+}}(aq)||F{e}^{2+}(aq)∣Fe\)
is \(0.32 V\). Calculate the standard Gibbs energy change for the reaction:
\(Zn(s)+F{e}^{2+}(aq)\to Z{n}^{2+}(aq)+Fe(s)\)
(Given : \(1 F =96487 C\) )

[Re-NEET 2024]

Question

The standard cell potential of the following cell

\(Zn|Z{n}^{{2}^{+}}(aq)||F{e}^{2+}(aq)∣Fe\)
is \(0.32 V\). Calculate the standard Gibbs energy change for the reaction:
\(Zn(s)+F{e}^{2+}(aq)\to Z{n}^{2+}(aq)+Fe(s)\)
(Given : \(1 F =96487 C\) )

[Re-NEET 2024]

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The standard cell potential of the following cell \(Zn|Z{n}^{{2}^{+}}(aq)||F{e}^{2+}(aq)∣Fe\) is \(0.32 V\). Calculate t…

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