When a metal surface is illuminated by a wavelength \(\lambda\), the maximum kinetic energy of the ejected electrons is …

When a metal surface is illuminated by a wavelength \(\lambda\), the maximum kinetic energy of the ejected electrons is \(2\text{ }\text{eV}\). If the metal is illuminated by a wavelength \(\lambda \mathrm{/}2\), what will be the maximum kinetic energy? (Work function \(ϕ=1\text{ }\text{eV}\))

(Shift II Memory Based)