The waves associated with a moving electron and a moving proton have the same wavelength \(\lambda\). It implies that th…

de brogle wavelength is given by

\(\lambda =\frac{\mathrm{h}}{\mathrm{p}}\\ \mathrm{here},\mathrm{wavelength}\mathrm{is}\mathrm{same}\mathrm{for}\mathrm{electron}\mathrm{and}\mathrm{proton},\\ \mathrm{so}\mathrm{the}\mathrm{momentum}\mathrm{is}\mathrm{also}\mathrm{same}\mathrm{for}\mathrm{eletron}\mathrm{and}\mathrm{proton}.\)