🏫 Board🧲 Physics

The angle between vector \(\vec{Q}\) and the resultant of \((2\vec{Q}+2\vec{P})\) and \((2\vec{Q}-2\vec{P})\) is

Q1 FREE PREVIEW

The angle between vector \(\vec{Q}\) and the resultant of \((2\vec{Q}+2\vec{P})\) and \((2\vec{Q}-2\vec{P})\) is

a

\(0^\circ\)

b

\({\tan }^{-1}\frac{P}{Q}\)

c

\({\tan }^{-1}\left(\frac{2\vec{Q}-2\vec{P}}{2\vec{Q}+2\vec{P}}\right)\)

d

\({\tan }^{-1}(2Q/P)\)

✓ Correct answer: a)

\(0^\circ\)

Explanation

Let the resultant of both the vectors be \(\vec{R}\), then

\begin{equation}
\begin{aligned}
&\begin{aligned}
\vec{R} & =(2 \vec{Q}+2 \vec{P})+(2 \vec{Q}-2 \vec{P}) \\
\vec{R} & =4 \vec{Q}
\end{aligned}\\
&\text { Angle between } \vec{Q} \text { and } \vec{R} \text { is zero }
\end{aligned}
\end{equation}

Practice more Board Physics PYQs

See every question on Mathematical Tools and Vectors, or browse the full Board question bank.

See all questions on Mathematical Tools and Vectors →