A beaker is filled with water (refractive index \(\frac{4}{3}\)) upto a height H . A coin is placed at its bottom. The d…

The apparent depth (\({d}_{a}\)) is given by the formula:

\({d}_{a}=\frac{d}{n}\)​

where \(d\)is the actual depth of the coin and \(n\) is the refractive index of the medium (water in this case).

\({d}_{a}=\frac{H}{\frac{4}{3}}\)​

To solve this, multiply \(H\) by the reciprocal of \(\frac{4}{3}\):

\({d}_{a}=H\times \frac{3}{4}=\frac{3H}{4}\)​