A point object is placed in air at a distance of 4R on the principal axis of a convex spherical surface of radius of cur…
A point object is placed in air at a distance of 4R on the principal axis of a convex spherical surface of radius of curvature R separating two mediums, air and glass. As the object is moved towards the surface, the image formed is :
first real and then virtual
To determine the nature of the image formed by a convex spherical surface separating air and glass, we need to consider the refraction of light at the convex surface. The nature of the image (real or virtual) depends on the position of the object relative to the focal point of the convex surface.
Identify the given parameters: object distance (\(u = -4R\)), radius of curvature (\(R\)), and the refractive indices of air (\(n1 = 1\)) and glass (\(n2 > 1\)).
Use the refraction formula for a spherical surface:
\(\frac{n_2}{v} - \frac{n_1}{u} = \frac{n_2 - n_1}{R}\)
where \(u\) is the object distance, \(v\) is the image distance, and \(R\) is the radius of curvature.
Substitute the given values into the formula:
\(\frac{n_2}{v} - \frac{1}{-4R} = \frac{n_2 - 1}{R}\)
Solve for the image distance \(v\). As the object moves towards the surface (\(u\) increases from \(-4R\) to \(0\)), analyze how the image distance \(v\) changes. Initially, when the object is far (\(u = -4R\)), the image is virtual. As the object moves closer to the surface, the image becomes real when the object is within the focal length of the convex surface.
Final Answer:
D. first real and then virtual
Practice more Board Physics PYQs
See every question on Ray Optics and Optical Instruments, or browse the full Board question bank.
See all questions on Ray Optics and Optical Instruments →