Let the relation $R$ on the set $\text{M}=\left{1,2,3,\ldots ,16\right}$ be given by $\text{R}=\left{\left(x,y\right):4y=5x−3,x,y\in \text{M}\right}$. Then the minimum number of elements required to be added in $R,$ in order to make the relation symmetric, is equal to [JEE Main 2026, 22 Jan (Shift 1)]

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Correct answer: b) 2. Given, $\text{R}=\left{\left(x,y\right):4y=5x−3,x,y\in \text{M}\right}$ and $\text{M}=\left{1,2,3,\ldots ,16\right}$ $R=\left{\left(3,3\right),\left(7,8\right),\left(11,13\right)\right}$ To make it symmetric $(8,7),(13,11)$ must be added.

Let the relation \(R\) on the set \(\text{M}=\left{1,2,3,\ldots ,16\right}\) be given by \(\text{R}=\left{\left(x,y\righ…

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