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What is the dimensional formula of \(a{b}^{-1}\) in the equation \(\left(P+\frac{a}{{V}^{2}}\right)(V-b)=RT\), where let…

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What is the dimensional formula of \(a{b}^{-1}\) in the equation \(\left(P+\frac{a}{{V}^{2}}\right)(V-b)=RT\), where letters have their usual meaning.

[JEE Main 2024, 5 Apr (Shift 2)]

a

\(\left[{M}^{0}{L}^{3}{T}^{-2}\right]\)

b

\(\left[M{L}^{2}{T}^{-2}\right]\)

c

\(\left[{M}^{-1}{L}^{5}{T}^{3}\right]\)

d

\(\left[{M}^{6}{L}^{7}{T}^{4}\right]\)

✓ Correct answer: b)

\(\left[M{L}^{2}{T}^{-2}\right]\)

Explanation

\begin{equation}
\begin{aligned}
&\begin{aligned}
& {[P]=\left[\frac{a}{v^2}\right]} \\
& \Rightarrow[a]=\left[P V^2\right] \\
& {[a]=\left[M L^{-1} T^{-2} L^6\right]=\left[M L^5 T^{-2}\right]}
\end{aligned}\\
&\text { Now, }[v]=[b]\\
&\begin{aligned}
& {[b]=\left[L^3\right]} \\
& \therefore\left[a b^{-1}\right]=\left[M L^5 T^{-2} L^{-3}\right]=\left[M L^2 T^{-2}\right]
\end{aligned}
\end{aligned}
\end{equation}

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