What is the dimensional formula of \(a{b}^{-1}\) in the equation \(\left(P+\frac{a}{{V}^{2}}\right)(V-b)=RT\), where let…
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What is the dimensional formula of \(a{b}^{-1}\) in the equation \(\left(P+\frac{a}{{V}^{2}}\right)(V-b)=RT\), where letters have their usual meaning.
[JEE Main 2024, 5 Apr (Shift 2)]
✓ Correct answer: b)
\(\left[M{L}^{2}{T}^{-2}\right]\)
Explanation
\begin{equation}
\begin{aligned}
&\begin{aligned}
& {[P]=\left[\frac{a}{v^2}\right]} \\
& \Rightarrow[a]=\left[P V^2\right] \\
& {[a]=\left[M L^{-1} T^{-2} L^6\right]=\left[M L^5 T^{-2}\right]}
\end{aligned}\\
&\text { Now, }[v]=[b]\\
&\begin{aligned}
& {[b]=\left[L^3\right]} \\
& \therefore\left[a b^{-1}\right]=\left[M L^5 T^{-2} L^{-3}\right]=\left[M L^2 T^{-2}\right]
\end{aligned}
\end{aligned}
\end{equation}
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