The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) are

Step-by-step Short Solution:
- Potassium (Z = 19)

Electron configuration:

\[
1 s^2 2 s^2 2 p^6 3 s^2 3 p^6 4 s^1
\]

• The outermost electron is in the 4 s orbital, so:
• Principal quantum number \(n=4\)
• Azimuthal quantum number \(l=0\) (since it's an 's' orbital)
• Magnetic quantum number \(m=0\) (only one value for \(l=0\) )
• Spin quantum number \(s=+\frac{1}{2}\) (assumed to be \(+1 / 2\) for the first electron)

Final Answer:
A) \(n=4, l=0, m=0, s=+\frac{1}{2}\)