D and E are points on side AB and AC of △ABC. DE is parallel to BC. If AD:DB = 1 : 4 and area of △ADE is 6 sq cm, what is the ratio of area of △ADE : area of quadrilateral BDEC?

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Correct answer: d) 1: 24. | | SSC Let, AD = x and DB = 4x AB = AD+DB = 5x The ratio of the area of similar triangles is equal to the square of the ratio of their corresponding sides. Ar(ABC) = 150 sq cm Area of quadrilateral BDEC = Area of ABC - Area of ADE = 150 - 6 = 144 sq cm Area of ADE/Area of quadrilateral BDEC = Hence, Option D is the correct answer.

D and E are points on side AB and AC of △ABC. DE is parallel to BC. If AD:DB = 1 : 4 and area of △ADE is 6 sq cm, what i…

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