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An AC current is given by \(I={I}_{1}\sin \omega t+{I}_{2}\cos \omega t\) . A hot wire ammeter will give a reading: [JEE…

Q1

An AC current is given by \(I={I}_{1}\sin \omega t+{I}_{2}\cos \omega t\) . A hot wire ammeter will give a reading:

[JEE Main 2021, 17 Mar (Shift 1)]

a

\(\frac{{l}_{1}+{I}_{2}}{2\sqrt{2}}\)

b

\(\sqrt{\frac{{l}_{1}^{2}+{I}_{2}^{2}}{2}}\)

c

\(\frac{{I}_{1}+{I}_{2}}{\sqrt{2}}\)

d

\(\sqrt{\frac{{l}_{1}^{2}-{I}_{2}^{2}}{2}}\)

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