In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of \(2.0\times {10}^{10}\mathrm{Hz}\) and amplitude \(48{\mathrm{Vm}}^{-1}\). Then the amplitude of oscillating magnetic field is : (Speed of light in free space \(=3\times {10}^{8}\mathrm{m}{\mathrm{s}}^{-1}\))

[NEET 2023]

Question

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of \(2.0\times {10}^{10}\mathrm{Hz}\) and amplitude \(48{\mathrm{Vm}}^{-1}\). Then the amplitude of oscillating magnetic field is : (Speed of light in free space \(=3\times {10}^{8}\mathrm{m}{\mathrm{s}}^{-1}\))

[NEET 2023]

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