An electron accelerated through a potential difference \(V_1\) has a de-Broglie wavelength of \(\lambda\). When the pote…
Q1
An electron accelerated through a potential difference \(V_1\) has a de-Broglie wavelength of \(\lambda\). When the potential is changed to \(V_2\), its de-Broglie wavelength increases by \(50 \%\). The value of \(\left(\frac{V_1}{V_2}\right)\) is equal to:
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