If earth has a mass nine times and radius twice that of a planet \(P\). Then \(\frac{v_e}{3} \sqrt{x} m^{-1}\) will be t…

If earth has a mass nine times and radius twice that of a planet \(P\). Then \(\frac{v_e}{3} \sqrt{x} m^{-1}\) will be the minimum velocity required by a rocket to pull out of gravitational force of \(P\), where \(v_e\) is escape velocity on earth. The value of \(x\) is

[JEE Main 2023, 1 Feb (Shift 1)]