The magnetic field vector of an electromagnetic wave is given by \(B={B}_{0}\frac{\overset{^}{i}+\overset{^}{j}}{\sqrt{2…

The magnetic field vector of an electromagnetic wave is given by \(B={B}_{0}\frac{\overset{^}{i}+\overset{^}{j}}{\sqrt{2}}\cos (kz-\omega t)\) where \(\overset{^}{i},\overset{^}{j}\) represents unit vector along x and y-axis respectively. At t = 0s, two electric charges \({q}_{1}\) of \(4\pi\) coulomb and \({q}_{2}\) of \(2\pi\) coulomb located at \(\left(0,0,\frac{\pi }{k}\right)\) and \(\left(0,0,\frac{3\pi }{k}\right)\) respectively, have the same velocity of \(0.5c\overset{^}{i}\) (where c is the velocity of light). The ratio of the force acting on charge \({q}_{1}\) to \({q}_{2}\) is :