Two conducting circular loops of radii $ R_{1} $ and $ R_{2} $ are placed in the same plane with their centres coinciding. If $ R_{1}R_{2} $, the mutual inductance $ M $ between them will be directly proportional to [NEET 2021]

Question

Two conducting circular loops of radii $ R_{1} $ and $ R_{2} $ are placed in the same plane with their centres coinciding. If $ R_{1}>R_{2} $, the mutual inductance $ M $ between them will be directly proportional to [NEET 2021]

YESPYQ · Accepted Answer

Correct answer: d) $ \frac{R_{2}^{2}}{R_{1}} $. Magnetic field due to R 1 at the center $B=\frac{{\mu }_{0}i}{2{R}_{1}}$ Flux linked with R 2 $ϕ=B{A}_{2}=\frac{{\mu }_{0}i}{2{R}_{1}}\times \pi {R}_{2}^{2}=Mi$ $M=\frac{{\mu }_{0}\pi {R}_{2}^{2}}{2{R}_{1}}$ $M\propto \frac{{R}_{2}^{2}}{{R}_{1}}$ (NEW NCERT 12 th Page No. 164, 165, 166, 167, 168 and 169)

Two conducting circular loops of radii \( R_{1} \) and \( R_{2} \) are placed in the same plane with their centres coinc…

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