The amount of glucose required to prepare $250\mathrm{mL}$ of $\frac{M}{20}$ aqueous solution is:
(Molar mass of glucose : $180\mathrm{g}{\mathrm{mol}}^{-1}$)

Question

The amount of glucose required to prepare $250\mathrm{mL}$ of $\frac{M}{20}$ aqueous solution is: (Molar mass of glucose : $180\mathrm{g}{\mathrm{mol}}^{-1}$)

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

The amount of glucose required to prepare \(250\mathrm{mL}\) of \(\frac{M}{20}\) aqueous solution is: (Molar mass of glu…

Practice more NEET Chemistry PYQs