The value of electric potential at a distance of 9 cm from the point charge $4\times {10}^{-7}\mathrm{C}$ is [Given $\left.\frac{1}{4\pi {\epsilon }_{0}}=9\times {10}^{9}{\mathrm{Nm}}^{2}{\mathrm{C}}^{-2}\right]$ :

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Correct answer: d) $4\times {10}^{4}\mathrm{V}$. $V=\frac{9\times {10}^{9}\times 4\times {10}^{-7}}{9\times {10}^{-2}}\ V=4\times {10}^{4}V$

The value of electric potential at a distance of 9 cm from the point charge \(4\times {10}^{-7}\mathrm{C}\) is [Given \(…

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