Motion in a Plane
5 NEET Physics previous year questions on Motion in a Plane — options free on every question; 1 include the answer & explanation free, the rest unlock with PYQ Pass.
The trajectory of projectile, projected from the ground is given by \(y=x-\frac{{x}^{2}}{20}\). Where x and y are measured in meter. The maximum height attained by the projectile will be:
\(5\mathrm{m}\)
\(y=x-\frac{{x}^{2}}{20}\)
For maximum height,
\(\frac{dy}{dx}=0\Rightarrow \frac{d}{dx}\left(x-\frac{{x}^{2}}{20}\right)=0\\ 1-\frac{2x}{20}=0\\ x=10\)
So, \({y}_{\max }=10-\frac{100}{20}=5m\)
A bullet is fired from a gun at the speed of \(280{\mathrm{ms}}^{-1}\) in the direction \(30^\circ\) above the horizontal. The maximum height attained by the bullet is \(\left(\mathrm{g}=9.8{\mathrm{ms}}^{-2},\sin 30^\circ =0.5\right)\):-
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The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is
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A car starts from rest and accelerates at \( 5 \mathrm{~m} / \mathrm{s}^{2} \). At \( \mathrm{t}=4 \mathrm{~s} \), a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at \( \mathrm{t}=6 \mathrm{~s} \) ?
[NEET 2021]
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A particle moving in a circle of radius \( \mathrm{R} \) with a uniform speed takes a time \( \mathrm{T} \) to complete one revolution. If this particle were projected with the same speed at an angle \( \theta \) to the horizontal, the maximum height attained by it equals \( 4 \mathrm{R} \). The angle of projection, \( \theta \), is then given by:
[NEET 2021]
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