Mechanical Properties of Solids
5 NEET Physics previous year questions on Mechanical Properties of Solids — options free on every question; 1 include the answer & explanation free, the rest unlock with PYQ Pass.
The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young's modulus, respectively, are \(8\times {10}^{8}\mathrm{N}{\mathrm{m}}^{-2}\) and \(2\times {10}^{11}\mathrm{N}{\mathrm{m}}^{-2}\), is :
[NEET 2024]
4 mm
Under the elastic limit, the maximum permissible stress = \(8\times {10}^{8}\text{ }\mathrm{N}\mathrm{/}{\mathrm{m}}^{2}\). Since
\(\text{strain}\text{ }=\text{ }\frac{\text{stress}}{Y},\ \Delta L\text{ }=\text{ }\text{(strain)}\times L,\)
we get
\({\mathrm{ΔL}}_{\max }=(\frac{8\times {10}^{8}}{2\times {10}^{11}})\times 1\text{ }\mathrm{m}=4\times {10}^{−3}\text{ }\mathrm{m}=4\text{ }\mathrm{m}\mathrm{m}\mathrm{.}\)
Match List I with List II :
| List I | List II |
| A. Young's Modulus | I. \(\frac{\Delta d}{\Delta L}\left(\frac{L}{d}\right)\) |
| B. Compressibility | II. \(\frac{FL}{A(\Delta L)}\) |
| C. Bulk Modulus | III. \(-\frac{1}{\Delta P}\left(\frac{\Delta V}{V}\right)\) |
| D. Poisson's Ratio | IV. \(-P\left(\frac{V}{\Delta V}\right)\) |
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A wire of length \( \mathrm{L} \) area of cross section \( \mathrm{A} \) is hanging from a fixed support. The length of the wire changes to \( L_{1} \) when mass \( M \) is suspended from its free end. The expression for Young's modulus is :
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A wire of length \( \mathrm{L} \) , area of cross section \( \mathrm{A} \) is hanging from a fixed support. The length of the wire changes to \( L_{1} \) when mass \( M \) is suspended from its free end. The expression for Young's modulus is :
[NEET 2020]
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An aluminium rod with Young's modulus \(Y=7.0 \times 10^{10}\) \(\mathrm{N} / \mathrm{m}^{2}\) undergoes elastic strain of \(0.04 \%\). The energy per unit volume stored in the rod in SI unit is:
[JEE Main 2023, 8 Apr (Shift 1)]
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