NEETPhysics

Mechanical Properties of Fluids

10 NEET Physics previous year questions on Mechanical Properties of Fluids — options free on every question; 1 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ

A submarine is designed to withstand an absolute pressure of 100 atm. How deep can it go below the water surface?

(Consider the density of water = 1000 kg m–3, 1 atm = 1 × 105 Pa and gravitational acceleration g = 10 m/s2)

a

9900 m

b

99 m

c

9000 m

d

990 m

✓ Correct answer: d)

990 m

Explanation

At depth h,

\({P}_{\text{absolute}}={P}_{\text{atm}}+\rho gh\)

Given:

\(100\text{atm}=1\text{atm}+\rho gh\)

\(\rho gh=99\text{atm}=99\times {10}^{5}\text{Pa}\)

\(h=\frac{99\times {10}^{5}}{1000\times 10}=990\text{m}\)

So, maximum depth = \(990\text{m}\).

Q2
PYQ

The venturi-meter works on:

a

Bernoulli's principle.

b

Pascal's law

c

excess pressure.

d

capillary action

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Q3
PYQ

A raindrop with radius \(\mathrm{R}=0.2 \mathrm{~mm}\) falls from a cloud at a height \(h=2000 \mathrm{~m}\) above the ground. Assume that the drop is spherical through its fall and the force of buoyance may be neglected, then the terminal speed attained by the raindrop is :

[Density of water \(f_{\mathrm{w}}=1000 \mathrm{kg m}^{-3}\) and Density of air \(f_{\mathrm{a}}=1.2 \mathrm{~kg}^{-3}, g=10 \mathrm{~m} / \mathrm{s}^{2}\), Coefficient of viscosity of air \(\left.=1.8 \times 10^{-5} \mathrm{Nsm}^{-2}\right]\)

a

\(4.94 \mathrm{~ms}^{-1}\)

b

\(14.4 \mathrm{~ms}^{-1}\)

c

\(43.56 \mathrm{~ms}^{-1}\)

d

\(250.6 \mathrm{~ms}^{-1}\)

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Q4
PYQ

An air bubble of volume \(1 \mathrm{~cm}^{3}\) rises from the bottom of a lake \(40 \mathrm{~m}\) deep to the surface at a temperature of \(12^{\circ} \mathrm{C}\). The atmospheric pressure is \(1 \times 10^{5} \mathrm{~Pa}\), the density of water is \(1000 \mathrm{~kg} / \mathrm{m}^{3}\) and \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\). There is no difference of the temperature of water at the depth of \(40 \mathrm{~m}\) and on the surface. The volume of air bubble when it reaches the surface will be

[JEE Main 2023, 8 Apr (Shift 1)]

a

\(5 \mathrm{~cm}^{3}\)

b

\(2 \mathrm{~cm}^{3}\)

c

\(4 \mathrm{~cm}^{3}\)

d

\(3 \mathrm{~cm}^{3}\)

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Q5
PYQ

A fully loaded aircraft has a mass of \(5.4 \times 10^{5} \mathrm{~kg}\). Its total wing area is \(500 \mathrm{~m}^{2}\). It is in level flight with a speed of \(1080 \mathrm{~km} / \mathrm{h}\). If the density of air is \(1.2 \mathrm{~kg} \mathrm{~m}^{-3}\), the fractional increase in the speed of the air on the upper surface of the wings relative to the lower surface in percentage will be \(\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

a

16

b

6

c

8

d

10

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Q6
PYQ

A capillary tube of radius \( r \) is immersed in water and water rises in it to a height \( h \). The mass of the water in the capillary is \( 5 \mathrm{~g} \). Another capillary tube of radius \( 2 r \) is immersed in water. The mass of water that will rise in this tube is:

[NEET 2020]

a

\( 5.0 \mathrm{~g} \)

b

\( 10.0 \mathrm{~g} \)

c

\( 20.0 \mathrm{~g} \)

d

\( 2.5 \mathrm{~g} \)

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Q7
PYQ

The velocity of a small ball of mass \( M \) and density \( d \), when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is \( \frac{d}{2} \), then the viscous force acting on the ball will be:

[NEET 2021]

a

\( 2 M g \)

b

\( \frac{M g}{2} \)

c

\( M g \)

d

\( \frac{3}{2} M g \)

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Q8
PYQ

A liquid does not wet the solid surface if angle of contact is

a

Equal to \( 60^{\circ} \)

b

Greater than \( 90^{\circ} \)

c

Zero

d

Equal to \( 45^{\circ} \)

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Q9
PYQ

A barometer is constructed using a liquid(density\(=760\mathrm{kg}/{\mathrm{m}}^{3}\)). What would be the height of the liquid column, when a mercury barometer reads \(76\mathrm{cm}\)? (density of mercury \(=13600\mathrm{kg}/{\mathrm{m}}^{3}\))

[Re-NEET 2020]

a

\(13.6\mathrm{m}\)

b

\(136\mathrm{m}\)

c

\(0.76\mathrm{m}\)

d

\(1.36\mathrm{m}\)

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Q10
PYQ

The amount of energy required to form a soap bubble of radius \(2\mathrm{cm}\) from a soap solution is nearly: (surface tension of soap solution \(=0.03\mathrm{N}{\mathrm{m}}^{-1}\) )

[NEET 2023]

a

\(5.06\times {10}^{-4}\mathrm{J}\)

b

\(3.01\times {10}^{-4}\mathrm{J}\)

c

\(50.1\times {10}^{-4}\mathrm{J}\)

d

\(30.16\times {10}^{-4}\mathrm{J}\)

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