Amines

Q1 FREE PREVIEW

PYQ

The action of nitrous acid on an aliphatic primary amine gives

asecondary amine

bnitro alkane

calcohol

dalkyl nitrite.

✓ Correct answer: c) alcohol

ExplanationAliphatic primary amines react with nitrous acid (HNO₂) to form alcohols with the evolution of nitrogen gas.Correct Answer: C) alcohol

Q2 FREE PREVIEW

PYQ

Given below are two statements: Statement-I: Aniline is less basic than acetamide. Statement-II: In aniline, the lone pair of electrons on nitrogen atom is delocalised over benzene ring due to resonance and hence less available to a proton. Choose the most appropriate option: [JEE Main 2020, 6 Sep (Shift 1)]

aStatement-I is true but Statement-II is false.

bStatement-I is false but Statement-II is true

cBoth Statement-I and Statement-II are true.

dBoth Statement-I and Statement-II are false.

✓ Correct answer: b) Statement-I is false but Statement-II is true

ExplanationIn triethyl amine, nitrogen is hybridized, so, bond angle is approximately around .Since, lone pair- bond pair repulsion is greater than bp-bp repulsion, hence, the exact angle is found to be .

Q3

PYQ

Which of the following reactions will NOT give primary amine as the product?

[NEET 2023]

a

\({\mathrm{CH}}_{3}\mathrm{CN}\overset{(\mathrm{i})\text{ }{\mathrm{LiAlH}}_{4}}{\underset{(\mathrm{ii})\text{ }{\mathrm{H}}_{3}{\mathrm{O}}^{+}}{\to }}\)Product

b

\({\mathrm{CH}}_{3}\mathrm{NC}\overset{(\mathrm{i})\text{ }{\mathrm{LiAlH}}_{4}}{\underset{(\mathrm{ii})\text{ }{\mathrm{H}}_{3}{\mathrm{O}}^{+}}{\to }}\) Product

c

\({\mathrm{CH}}_{3}{\mathrm{CONH}}_{2}\overset{(\mathrm{i})\text{ }{\mathrm{LiAlH}}_{4}}{\underset{(\mathrm{ii})\text{ }{\mathrm{H}}_{3}{\mathrm{O}}^{+}}{\to }}\)Product

d

\(\mathrm{CH}_3 \mathrm{CONH}_2 \xrightarrow{\mathrm{Br}_2 / \mathrm{KOH}}\) Product

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Q4

PYQ

Given below are two statements

Statement I : Benzenediazonium salt is prepared by the reaction of aniline with nitrous açid at \(273-278\mathrm{K}\). It decomposes easily in the dry state.

Statement II : Insertion of iodine into the benzene ring is difficult and hence iodobenzene is prepared through the reaction of benzenediazonium salt with KI.

In the light of the above statements, choose the most appropriate answer from the options given below

[NEET 2025]

a

Statement I is correct but Statement II is incorrect

b

Statement I is incorrect but Statement II is correct

c

Both Statement I and Statement II are correct

d

Both Statement I and Statement II are incorrect

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Q5

PYQ

4-nitrotoluene is treated with \({\mathrm{Br}}_{2}\) to get compound P which is reduced with Sn and HCl to get Compound Q, then Q is diazotized and the product is treated with phosphinic acid to get R, R is oxidized with alkaline \({\mathrm{KMnO}}_{4}\) to get the final product P. P is

a

2-Bromo-4-hydroxy Benzoic acid

b

Benzoic acid

c

4-Bromo Benzoic acid

d

2-Bromo Benzoic acid

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Q6

PYQ

Identify the major product \(C\) formed in the following reaction sequence
\({\mathrm{CH}}_{3}-{\mathrm{CH}}_{2}-{\mathrm{CH}}_{2}-\mathrm{I}\overset{\mathrm{NaCN}}{\to }\mathrm{A}\)

\(\overset{{\mathrm{OH}}^{-}}{\underset{\mathrm{Partial}\mathrm{hydrolysis}}{\to }}\mathrm{B}\overset{\mathrm{NaOH}}{\underset{{\mathrm{Br}}_{2}}{\to }}\underset{(\mathrm{major})}{\mathrm{C}}\)

a

\(\alpha\)-Bromobutanoic acid

b

Propylamine

c

Butylamine

d

Butanamide

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Q7

PYQ

Given below are two statements:

Statement I : Primary aliphatic amines react with \( \mathrm{HNO}_{2} \) to give unstable diazonium salts.

Statement II : Primary aromatic amines react with \( \mathrm{HNO}_{2} \) to form diazonium salts which are stable even above \( 300 \mathrm{~K} \).

In the light of the above Statements, choose the most appropriate answer from the options given below

[NEET 2022]

a

Statement I is incorrect but Statement II is correct.

b

Both Statement I and Statement II are correct

c

Both Statement I and Statement II are incorrect.

d

Statement I is correct but Statement II is incorrect.

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Q8

PYQ

The compound that does not undergo Friedel-Crafts alkylation reaction but gives a positive carbylamine test is

[Re-NEET 2024]

a

aniline

b

pyridine

c

\(N\)-methylaniline

d

triethylamine

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Q9

PYQ

Identify the major product \(C\) formed in the following reaction sequence
\({\mathrm{CH}}_{3}-{\mathrm{CH}}_{2}-{\mathrm{CH}}_{2}-\mathrm{I}\overset{\mathrm{NaCN}}{\to }\mathrm{A}\)

\(\overset{{\mathrm{OH}}^{-}}{\underset{\mathrm{Partial}\mathrm{hydrolysis}}{\to }}\mathrm{B}\overset{\mathrm{NaOH}}{\underset{{\mathrm{Br}}_{2}}{\to }}\underset{(\mathrm{major})}{\mathrm{C}}\)

[NEET-2024]

a

\(\alpha\)-Bromobutanoic acid

b

Propylamine

c

Butylamine

d

Butanamide

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Q10

PYQ

Given below are two statements:

Statement I : Aniline does not undergo Friedel Crafts alkylation reaction.

Statement II : Aniline cannot be prepared through Gabriel synthesis.

In the light of the above statements, choose the correct answer from the options given below

a

Statement I is false but Statement II is true.

b

Both Statement I and Statement II are true.

c

Both Statement I and Statement II are false.

d

Statement I is true but Statement II is false.

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Q11

PYQ

The correct order in aqueous medium of basic strength in case of methyl substituted amines is:

a

\({\mathrm{Me}}_{2}\mathrm{NH}>{\mathrm{MeNH}}_{2}>{\mathrm{Me}}_{3}\mathrm{N}>{\mathrm{NH}}_{3}\)

b

\({\mathrm{Me}}_{2}\mathrm{NH}>{\mathrm{Me}}_{3}\mathrm{N}>{\mathrm{MeNH}}_{2}>{\mathrm{NH}}_{3}\)

c

\({\mathrm{NH}}_{3}>{\mathrm{Me}}_{3}\mathrm{N}>{\mathrm{MeNH}}_{2}>{\mathrm{Me}}_{2}\mathrm{NH}\)

d

\({\mathrm{Me}}_{3}\mathrm{N}>{\mathrm{Me}}_{2}\mathrm{NH}>{\mathrm{MeNH}}_{2}>{\mathrm{NH}}_{3}\)

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Q12

PYQ

Match the colums and select the correct option (memory based jee mains shift-2 22/01/2025)

Column-I (Compound)	Column-II (Reducing agent for preparing primary amine)
(A) \({\mathrm{RCONH}}_{2}\)	(I) \(\mathrm{Na}/{\mathrm{C}}_{2}{\mathrm{H}}_{5}\mathrm{OH}\)
(B)\({\mathrm{PhNO}}_{2}\)	(II) \({\mathrm{LiAlH}}_{4}\)
(C) \(\mathrm{PhCN}\)	(III) \(\mathrm{R}-\mathrm{X}/\mathrm{aq}.\mathrm{NaOH}\)
(D) Phthalimide	(IV) \(\mathrm{Fe}/\mathrm{HCl}\)

a

A-II, B-IV, C-I, D-III

b

A-II, B-IV, C-III, D-I

c

A-III, B-IV, C-I, D-II

d

A-IV, B-II, C-I, D-III

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Q13

PYQ

Identify the compound that will react with Hinsberg's reagent to give a solid which dissolves in alkali

[NEET-2021]

a

\({\mathrm{CH}}_{3}{\mathrm{CH}}_{2}{\mathrm{NHCH}}_{3}\)

b

\({\mathrm{CH}}_{3}{\mathrm{CH}}_{2}{\mathrm{NH}}_{2}\)

c

\({\mathrm{CH}}_{3}{\mathrm{CH}}_{2}\mathrm{N}\left({\mathrm{CH}}_{3}\right){\mathrm{CH}}_{2}{\mathrm{CH}}_{3}\)

d

\({\mathrm{CH}}_{3}{\mathrm{CH}}_{2}{\mathrm{NO}}_{2}\)

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Q14

PYQ

Reaction of propanamide with ethanolic sodium hydroxide and bromine will give.

[Re-NEET 2020]

a

Methylamine

b

Propylamine

c

Aniline

d

Ethylamine

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Q15

PYQ

The correct order of the basic strength of methyl substituted amines in aqueous solution is:

[NEET 2019]

a

\( \left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N} \)

b

\( \left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH} \)

c

\( \left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}>\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2} \)

d

\( \mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N} \)

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