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If the sum of the series \( 20+19 \frac{3}{5}+19 \frac{1}{5}+18 \frac{4}{5}+\ldots . \). upto \( n \) terms is 488 and t…

Q1

If the sum of the series \( 20+19 \frac{3}{5}+19 \frac{1}{5}+18 \frac{4}{5}+\ldots . \). upto \( n \) terms is 488 and the \( n^{\text {th }} \) term is negative, then the value of \( n^{\text {th }} \) term is

[JEE Main 2020, 3 Sep (Shift 2)]

a

\( -4 \frac{2}{5} \)

b

\( -4 \)

c

\( -41 \)

d

\( -60 \)

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