If the equation of the normal to the curve $y=\frac{x-a}{(x+b)(x-2)}$ at the point $(1,-3)$ is $x-4 y=13$, then the value of $a+b$ is equal to........

[JEE Main 2023, 29 Jan (Shift 2)]

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If the equation of the normal to the curve $y=\frac{x-a}{(x+b)(x-2)}$ at the point $(1,-3)$ is $x-4 y=13$, then the value of $a+b$ is equal to........ [JEE Main 2023, 29 Jan (Shift 2)]

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If the equation of the normal to the curve \(y=\frac{x-a}{(x+b)(x-2)}\) at the point \((1,-3)\) is \(x-4 y=13\), then th…

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