🛠️ JEE➗ Maths

The minimum value of \(2^{\sin x}+2^{\cos x}\) is:

\({2}^{-1+\sqrt{2}}\)

\({2}^{1-\sqrt{2}}\)

\({2}^{1-\frac{1}{\sqrt{2}}}\)

\({2}^{-1+\frac{1}{\sqrt{2}}}\)

🔒

Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149

See every question on Sequence and Series, or browse the full JEE question bank.