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Find electrode potential at pH = 5 for 2H₂O → O₂ + 4H⁺ + 4e⁻ E° = -1.23 V [JEE Main 2020, 8 Jan (Shift 1)]

Q1

Find electrode potential at pH = 5 for

2H₂O → O₂ + 4H⁺ + 4e⁻
E° = -1.23 V

[JEE Main 2020, 8 Jan (Shift 1)]

a

-0.93

b

-0.83

c

+0.69

d

+0.96

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