Let $A=\left(\begin{array}{ccc}{[x+1]} & {[x+2]} & {[x+3]} \ {[x]} & {[x+3]} & {[x+3]} \ {[x]} & {[x+2]} & {[x+4]}\end{array}\right)$ where $[t]$ denotes the greatest integer less than or equal to $t$. If $\operatorname{det}(A)=192$, then the set of values of $x$ is the interval. [JEE Main 2021, 27 Aug (Shift 2)]

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Let \(A=\left(\begin{array}{ccc}{[x+1]} & {[x+2]} & {[x+3]} \\ {[x]} & {[x+3]} & {[x+3]} \\ {[x]} & …

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Let \(A=\left(\begin{array}{ccc}{[x+1]} &amp; {[x+2]} &amp; {[x+3]} \\ {[x]} &amp; {[x+3]} &amp; {[x+3]} \\ {[x]} &amp; …

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Let \(A=\left(\begin{array}{ccc}{[x+1]} & {[x+2]} & {[x+3]} \\ {[x]} & {[x+3]} & {[x+3]} \\ {[x]} & …