If [x] be the greatest integer less than or equal to x, then $\sum _{n=8}^{100}\left[\frac{(-1{)}^{n}n}{2}\right]$ is equal to:

[JEE Main 2021, 25 Jul (Shift 2)]

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If [x] be the greatest integer less than or equal to x, then $\sum _{n=8}^{100}\left[\frac{(-1{)}^{n}n}{2}\right]$ is equal to: [JEE Main 2021, 25 Jul (Shift 2)]

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If [x] be the greatest integer less than or equal to x, then \(\sum _{n=8}^{100}\left[\frac{(-1{)}^{n}n}{2}\right]\) is …

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