If \(\frac{{(x+1)}^{2}}{{x}^{3}+x}=\frac{A}{x}+\frac{Bx+C}{{x}^{2}+1}\), then \({\sin }^{−1}A+{\tan }^{−1}B+{\sec }^{−1}…
Q1
If \(\frac{{(x+1)}^{2}}{{x}^{3}+x}=\frac{A}{x}+\frac{Bx+C}{{x}^{2}+1}\), then \({\sin }^{−1}A+{\tan }^{−1}B+{\sec }^{−1}C=\)
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