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If a die is thrown twice, then the probability of getting 1 in the first throw only is

Q1

If a die is thrown twice, then the probability of getting 1 in the first throw only is

a

\(\frac{1}{36}\)

b

\(\frac{3}{36}\)

c

\(\frac{5}{36}\)

d

\(\frac{1}{6}\)

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