🛠️ JEE➗ Maths

If \(xy+{y}^{2}=\tan x+y\), then find \(\frac{dy}{dx}\) is

\(\frac{{\sec }^{2}x}{x+2y}\)

\(\frac{{\sec }^{2}x−y}{(x+2y−1)}\)

\((x+2y−1){\sec }^{2}x\)

\({\sec }^{2}x⋅y\)

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