The electrode potential of the following half cell at \(298 \mathrm{~K}\).

\(\mathrm{X}\left|\mathrm{X}^{2+}(0.001 \mathrm{M}) \| \mathrm{Y}^{2+}(0.01 \mathrm{M})\right| \mathrm{Y}\) is _______\(\times 10^{-2} \mathrm{~V}\) (Nearest integer).

Given: \(\begin{aligned} \mathrm{E}_{\mathrm{x}^{2+}{ }_{\mathrm{X}}}^0 & =-2.36 \mathrm{~V} \\ \mathrm{E}_{\mathrm{Y}^{2+} \mid \mathrm{Y}}^0 & =+0.36 \mathrm{~V}\end{aligned}\)

\(\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06 \mathrm{~V}\)

[JEE Main 2023, 30 Jan (Shift 2)]

Question

The electrode potential of the following half cell at \(298 \mathrm{~K}\).

\(\mathrm{X}\left|\mathrm{X}^{2+}(0.001 \mathrm{M}) \| \mathrm{Y}^{2+}(0.01 \mathrm{M})\right| \mathrm{Y}\) is _______\(\times 10^{-2} \mathrm{~V}\) (Nearest integer).

Given: \(\begin{aligned} \mathrm{E}_{\mathrm{x}^{2+}{ }_{\mathrm{X}}}^0 & =-2.36 \mathrm{~V} \\ \mathrm{E}_{\mathrm{Y}^{2+} \mid \mathrm{Y}}^0 & =+0.36 \mathrm{~V}\end{aligned}\)

\(\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06 \mathrm{~V}\)

[JEE Main 2023, 30 Jan (Shift 2)]

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