🛠️ JEE➗ Maths

The value of the integral \(\int_{-\log _e 2}^{\log _e 2} e^x\left(\log _e\left(e^x+\sqrt{1+e^{2 x}}\right)\right) d x\)…

Q1

The value of the integral \(\int_{-\log _e 2}^{\log _e 2} e^x\left(\log _e\left(e^x+\sqrt{1+e^{2 x}}\right)\right) d x\) is equal to

[JEE Main 2023, 11 Apr (Shift 1)]

a

\(\log _e\left(\frac{2(2+\sqrt{5})}{\sqrt{1+\sqrt{5}}}\right)-\frac{\sqrt{5}}{2}\)

b

\(\log _e\left(\frac{\sqrt{2}(3-\sqrt{5})^2}{\sqrt{1+\sqrt{5}}}\right)+\frac{\sqrt{5}}{2}\)

c

\(\log _e\left(\frac{(2+\sqrt{5})^2}{\sqrt{1+\sqrt{5}}}\right)+\frac{\sqrt{5}}{2}\)

d

\(\log _e\left(\frac{\sqrt{2}(2+\sqrt{5})^2}{\sqrt{1+\sqrt{5}}}\right)-\frac{\sqrt{5}}{2}\)

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