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Let \(9=x_1<x_2<\ldots<x_7\) be in an A.P. with common difference \(d\). If the standard deviation of \(x_1, x_…

Q1

Let \(9=x_1<x_2<\ldots<x_7\) be in an A.P. with common difference \(d\). If the standard deviation of \(x_1, x_2 \ldots, x_7\) is 4 and the mean is \(\bar{x}\), then \(\bar{x}+x_6\) is equal to:

[JEE Main 2023, 1 Feb (Shift 2)]

a

\(18\left(1+\frac{1}{\sqrt{3}}\right)\)

b

34

c

\(2\left(9+\frac{8}{\sqrt{7}}\right)\)

d

25

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