🛠️ JEE➗ Maths

\(\int_{\frac{3 \sqrt{2}}{4}}^{\frac{3 \sqrt{3}}{4}} \frac{48}{\sqrt{9-4 x^2}} d x\) is equal to

Q1

\(\int_{\frac{3 \sqrt{2}}{4}}^{\frac{3 \sqrt{3}}{4}} \frac{48}{\sqrt{9-4 x^2}} d x\) is equal to

a

\(\frac{\pi}{3}\)

b

\(\frac{\pi}{2}\)

c

\(\frac{\pi}{6}\)

d

\(2 \pi\)

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