Let \(\text{f}:\text{R}-\left{\frac{\alpha }{6}\right}\to \text{R}\) be defined by \(\text{f}(\text{x})=\frac{5\text{x}+…

Let \(\text{f}:\text{R}-\left{\frac{\alpha }{6}\right}\to \text{R}\) be defined by \(\text{f}(\text{x})=\frac{5\text{x}+3}{6\text{x}-\alpha }.\) Then the value of \(\alpha\) for which \((fof)(x)=x,\) for all \(x\in R-\left{\frac{\alpha }{6}\right},\) is:

[JEE Main 2021, 20 Jul (Shift 2)]