A beam of protons with speed \(4 \times 10^5 \mathrm{~ms}^{-1}\) enters a uniform magnetic field of \(0.3 \mathrm{~T}\) …

A beam of protons with speed \(4 \times 10^5 \mathrm{~ms}^{-1}\) enters a uniform magnetic field of \(0.3 \mathrm{~T}\) at an angle of \(60^{\circ}\) to the magnetic field. The pitch of the resulting helical path of protons is close to: (Mass of the proton = \(1.67 \times 10^{-27} \mathrm{~kg}\), charge of the proton \(=1.69 \times 10^{-19} \mathrm{C}\) )

[JEE mains 2020]