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Let \(g(x)=\int_0^x f(t) d t\), where \(f\) is continuous function in \([0,3]\) such that \(\frac{1}{3} \leq f(t) \leq 1…

Q1

Let \(g(x)=\int_0^x f(t) d t\), where \(f\) is continuous function in \([0,3]\) such that \(\frac{1}{3} \leq f(t) \leq 1\) for all \(t \in[0,1]\) and \(0 \leq f(t) \leq \frac{1}{2}\) for all \(t \in(1,3]\). The largest possible interval in which \(g (3)\) lies is:

[JEE Main 2021, 18 Mar (Shift 2)]

a

\([1,3]\)

b

\(\left[\frac{1}{3}, 2\right]\)

c

\(\left[-1,-\frac{1}{2}\right]\)

d

\(\left[-\frac{3}{2},-1\right]\)

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