The equation of a circle is given by \({x}^{2}+{y}^{2}={a}^{2}\), where a is the radius. If the equation is modified to …
Q1
The equation of a circle is given by \({x}^{2}+{y}^{2}={a}^{2}\), where a is the radius. If the equation is modified to change the origin other than (0,0), then find out the correct dimensions of \(A\) and \(B\) in a new equation: \((x-At{)}^{2}+{\left(y-\frac{t}{B}\right)}^{2}={a}^{2}\). The dimensions of t is given as \(\left[{T}^{-1}\right]\).
[JEE Main 2023, 29 Jan (Shift 2)]
🔒
Answer & explanation — PYQ Pass
Unlock · ₹149
Options are free to see. Unlock the correct answer and full explanation with Pass.
Practice more JEE Physics PYQs
See every question on Units and Measurements, or browse the full JEE question bank.
See all questions on Units and Measurements →